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• 产品描述： Ro 25-6981 Maleate is a potent, selective and activity-dependent NR2B subunit specific NMDA receptor antagonist. Ro 25-6981 Maleat shows anticonvulsant and anti-parkinsonian activity. Ro 25-6981 Maleate has the potential for the research of parkinson's disease (PD)

• 靶点： iGluR;Others

• 体内研究：
  Ro 25-6981 Maleate (0.39-12.5 mg/kg; i.p.) induces contraversive rotations in 6-hydroxydopamine (6-OHDA)-lesioned rats without stimulating locomotion in normal rats. Ro 25-6981 Maleate (1,3 mg/kg; i.p.) exhibits age- and activation-dependent anticonvulsant action at early postnatal development in rats. Ro 25-6981 Maleate (800 µg; intrathecal injection) shows significant analgesic effects on incision pain in rats and effectively attenuated postoperative hyperalgesia induced by remifentanil. Animal Model: 6-OHDA-lesioned rats Dosage: 0.39-12.5 mg/kg Administration: I.p. Result: Dose-dependently induced contraversive tight nose-to-tail rotations, and induced a weak ipsiversive circling response indicating a mild unspecific stimulatory action of the compound. Animal Model: Male albino rats of Wistar strain Dosage: 1, 3 mg/kg Administration: I.p. Result: Caused a significant decrease of N1–P2 amplitude at higher stimulation intensities AT 3 mg/kg, and exhibited age- and activation-dependent anticonvulsant action at early postnatal development.

• 参考文献：
  1. Löschmann PA, et al. Antiparkinsonian activity of Ro 25-6981, a NR2B subunit specific NMDA receptor antagonist, in animal models of Parkinson's disease. Exp Neurol. 2004 May;187(1):86-93. 2. Szczurowska E,et al. Different action of a specific NR2B/NMDA antagonist Ro 25-6981 on cortical evoked potentials and epileptic afterdischarges in immature rats. Brain Res Bull. 2015 Feb;111:1-8. 3. Jiang M, et al. Antinociception and prevention of hyperalgesia by intrathecal administration of Ro 25-6981, a highly selective antagonist of the 2B subunit of N-methyl-D-aspartate receptor. Pharmacol Biochem Behav. 2013 Nov;112:56-63.

• 溶解性： Soluble  in  DMSO、H2O

• 保存条件： -20℃

• 配置溶液浓度参考：
  

  	1mg	5mg	10mg
  1 mM	2.195 ml	10.976 ml	21.952 ml
  5 mM	0.439 ml	2.195 ml	4.39 ml
  10 mM	0.22 ml	1.098 ml	2.195 ml
  50 mM	0.044 ml	0.22 ml	0.439 ml

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本计算器可帮助您计算出特定溶液中溶质的质量、溶液浓度和体积之间的关系，公式为：

质量 (mg) = 浓度 (mM) x 体积 (mL) x 分子摩尔量 (g/mol)

• pg ng μg mg g kg =
  fM pM nM μM mM M *
  nL μL mL L *