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S86859

Narlaprevir

源叶(MedMol) 98%
  • 英文名:
  • Narlaprevir
  • 别名:
  • CAS号:
  • 865466-24-6
  • 分子式:
  • C36H61N5O7S
  • 分子量:
  • 707.96
品牌货号产品规格价格(RMB) 库存(上海) 北京 武汉 南京 数量计量单位 加入购物车...
源叶(MedMol) S86859-10mg 98% ¥4800.00元 预计交期:2-3天 - - - EA 加入购物车
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  • 提示:详情请下载说明书。
  • 产品描述: Narlaprevir (SCH 900518) is a selective and orally bioavailable NS3 protease inhibitor with a Ki value of 6 nM and an EC90 value of 40 nM. Narlaprevir also inhibits the HCV nonstructural protein 3 serine protease. Narlaprevir is also a SARS-CoV 3CLpro inhibitor with an IC50 of 2.3 μM
  • 靶点: Ki: 6 nM (NS3 protease) EC90: 40 nM (NS3 protease) Ki: 7 nM (ketoamide) EC90: 40 nM (replicon RNA)
  • 体内研究:
    Pharmacokinetic AnalysisNarlaprevir (SCH 900518) exhibits middle oral bioavailability (rat 46%, dog 29%, monkey 46 %) following oral administration (rat 10 mg/kg, dog 3 mg/kg, monkey 3 mg/kg ). Narlaprevir (SCH 900518) exhibits moderate half-lives (rat 4.8 and dog 2 h) following intravenous administration (rat 4 and dog 1 mg/kg). Animal Model: rats, dogs, monkeys Dosage: Rat PO/IV 10/4 mg/kg; dog PO/IV 3/1 mg/kg; monkey PO 3 mg/kg Administration: Intravenous (i.v.) or oral gavage Result: T1/2s of 4.8 and 2 h for rats and dogs, respectively.
  • 参考文献:
    1. Ashok Arasappan, et al. Discovery of Narlaprevir (SCH 900518): A Potent, Second Generation HCV NS3 Serine Protease Inhibitor. ACS Med Chem Lett. 2010 Feb 15;1(2):64-9. 2. X Tong, et al. Preclinical characterization of the antiviral activity of SCH 900518 (narlaprevir), a novel mechanism-based inhibitor of hepatitis C virus NS3 protease. Antimicrob Agents Chemother. 2010 Jun;54(6):2365-70. 3. Qi Sun, et al. Bardoxolone and bardoxolone methyl, two Nrf2 activators in clinical trials, inhibit SARS-CoV-2 replication and its 3C-like protease. Signal Transduct Target Ther. 2021 May 29;6(1):212.
  • 溶解性: Soluble  in  DMSO
  • 保存条件: -20℃
  • 配置溶液浓度参考:
    1mg 5mg 10mg
    1 mM 1.413 ml 7.063 ml 14.125 ml
    5 mM 0.283 ml 1.413 ml 2.825 ml
    10 mM 0.141 ml 0.706 ml 1.413 ml
    50 mM 0.028 ml 0.141 ml 0.283 ml
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质量 (mg) = 浓度 (mM) x 体积 (mL) x 分子摩尔量 (g/mol)


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