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• 产品描述： PF-AKT400 is a broadly selective, potent, ATP-competitive Akt inhibitor, displays 900-fold greater selectivity for PKBα (IC50=0.5 nM) than PKA (IC50=450 nM).

• 靶点： PKBα：0.5 nM (IC50)；PKA：450 nM (IC50);Akt

• 体内研究：
  PF-AKT400 is subsequently evaluated for modulation of Akt in tumors and in multiple in vivo mouse models of antitumor efficacy. It is active in a PC3 prostate carcinoma xenograft experiment, with 75% TGI observed at 100 mg/kg b.i.d. dosing for 10 days. In a colorectal carcinoma (Colo205) xenograft study, PF-AKT400 produces 60% TGI at 150 mg/kg b.i.d. after 10 days. Most intriguingly, in combination with Rapamycin (10 mg/kg, ip), 75 mg/kg b.i.d. (10 days) of PF-AKT400 results in 98% TGI in an additional PC3 prostate carcinoma xenograft study compared to 56% TGI and 66% TGI with PF-AKT400 and Rapamycin as single agents. To define the in vivo potency of PF-AKT400 (Compound 42) in the PC3 xenograft model, oral administration of 25, 75, and 100 mg/kg PF-AKT400 is performed with blood and tumor sampling over time. Immunoblot analysis of detergent-soluble extracts derived from PC3 tumors shows a significant reduction of S6 phosphorylation, and hyperphosphorylation of Akt upon treatment at doses that produced significant tumor growth inhibition. Plasma drug concentrations peak rapidly after oral administration of doses between 25-100 mg/kg (Tmax=0.5 h). Peak PD responses of phospho-S6 and phospho-Akt are observed at approximately 2-4h and 1h post-administration of PF-AKT400, respectively. The time-course of PD marker response is well described by a PK/PD model at doses that ranged from no efficacy (25 mg/kg) to maximal efficacy (100 mg/kg)

• 参考文献：
  1. Chen SF, et al. Binding selectivity studies of PKBα using molecular dynamics simulation and free energy calculations. J Mol Model. 2013 Nov;19(11):5097-5112. 2. Freeman-Cook KD, et al. Design of selective, ATP-competitive inhibitors of Akt. J Med Chem. 2010 Jun 24;53(12):4615-4622.

• 溶解性： Soluble  in  DMSO

• 保存条件： 2-8℃

• 配置溶液浓度参考：
  

  	1mg	5mg	10mg
  1 mM	2.497 ml	12.487 ml	24.973 ml
  5 mM	0.499 ml	2.497 ml	4.995 ml
  10 mM	0.25 ml	1.249 ml	2.497 ml
  50 mM	0.05 ml	0.25 ml	0.499 ml

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本计算器可帮助您计算出特定溶液中溶质的质量、溶液浓度和体积之间的关系，公式为：

质量 (mg) = 浓度 (mM) x 体积 (mL) x 分子摩尔量 (g/mol)

• pg ng μg mg g kg =
  fM pM nM μM mM M *
  nL μL mL L *