欢迎光临源叶生物,登录 | 注册 |
当前位置: 首页 > 小分子抑制剂 > DNADamage/DNARepair > GJ103 (sodium salt)

浏览历史

S83417

GJ103 (sodium salt)

源叶(MedMol) 98%
  • 英文名:
  • GJ103 (sodium salt)
  • 别名:
  • CAS号:
  • 1459687-96-7
  • 分子式:
  • C16H13N4NaO3S
  • 分子量:
  • 364.35418928
  • 核磁/质谱:
品牌货号产品规格价格(RMB) 库存(上海) 北京 武汉 南京 数量计量单位 加入购物车...
源叶(MedMol) S83417-1mg 98% ¥552.50元 10 - - - EA 加入购物车
源叶(MedMol) S83417-5mg 98% ¥765.00元 10 - - - EA 加入购物车
源叶(MedMol) S83417-10mg 98% ¥1232.50元 9 - - - EA 加入购物车
源叶(MedMol) S83417-50mg 98% ¥3200.00元 7 - - - EA 加入购物车
大包装询价

提交您的电话号码并同意《个人信息授权与保护申明》,到货后将短信提示。
提交

产品介绍

参考文献

质检证书(COA)

摩尔浓度计算器

相关产品

  • 提示:详情请下载说明书。
  • 产品描述: GJ103 sodium salt is an active analog of GJ072, a read-through compound.
  • 靶点: ATM/ATR
  • 体外研究:
    GJ072 induces ATM kinase on both TGA and TAG stop codons and restored ATMpSer1981 autophosphorylation and SMC1pSer966 transphosphorylation as measured by FACS. GJ072 is active in A-T cells with a homozygous TAA mutation. GJ072 is able to induce detectable full-length ATM protein in treated A-T cells. Early structure-activity relationship studies generates eight active analogs of GJ072. Some GJ072 analogs (e.g., GJ103, GJ106, GJ109, and GJ111) consistently demonstrates their activities in all three PTCs by both FCATMpSer1981 and IRIF assays. GJ071 and GJ072 and some of their analogs (such as GJ103) have similar read-through activity as RTC13 or RTC14, but are more tolerable than RTC13 and RTC14 to A-T cells. GJ103 does not show obvious cytotoxicity in A-T cells at concentration as high as 300 μM.
  • 体内研究:
    GJ103 sodium salt is water soluble, which will enable us to evaluate its in vivo activity by systematic administration.
  • 参考文献:
    1. Du L, et al. A new series of small molecular weight compounds induce read through of all three types of nonsense mutations in the ATM gene. Mol Ther. 2013 Sep;21(9):1653-60.
  • 溶解性: Soluble  in  DMSO
  • 保存条件: -20℃
  • 配置溶液浓度参考:
    1mg 5mg 10mg
    1 mM 2.745 ml 13.723 ml 27.446 ml
    5 mM 0.549 ml 2.745 ml 5.489 ml
    10 mM 0.274 ml 1.372 ml 2.745 ml
    50 mM 0.055 ml 0.274 ml 0.549 ml
  • 注意:部分产品我司仅能提供部分信息,我司不保证所提供信息的权威性,仅供客户参考交流研究之用。
输入产品批号:

本计算器可帮助您计算出特定溶液中溶质的质量、溶液浓度和体积之间的关系,公式为:


质量 (mg) = 浓度 (mM) x 体积 (mL) x 分子摩尔量 (g/mol)


  • =
    *
    *


源叶所有产品仅用作科学研究,销售产品行为均适用于我司网上所列通用销售条款。